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Q.
Two cells of emf $E_1$ and $ E_2$ are joined in opposition (such that $E_1> E_2$). If $r_1$ and $r_2$, be the internal resistance and $R$ be the external resistance, then the terminal potential difference is
Given, two cells of emf $E_{1}$ and $E_{2}$ are joined in opposition such that, $E_{1}>\,E_{2}$.
Current, $I=\frac{E_{1}-E_{2}}{r_{1}+r_{2}+R}$
Now, terminal potential difference across a circuit,
$V=I R $
$V=\left(\frac{E_{1}-E_{2}}{I_{1}+I_{2}+R}\right) R$
