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  4. Two cells connected in series have electromotive force of 1.5 V each. Their internal resistance are 0.5 Ω . and 0.25 Ω respectively. This combination is connected to a resistance of 2.25 Ω . Potential difference across the terminals of each cell

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Q. Two cells connected in series have electromotive force of 1.5 V each. Their internal resistance are $ 0.5\,\Omega $ . and $ 0.25\,\Omega $ respectively. This combination is connected to a resistance of $ 2.25\,\Omega $ . Potential difference across the terminals of each cellPhysics Question Image

JamiaJamia 2011

Solution:

The arrangement is shown in the figure. The effective emf in the circuit is $ E=1.5+1.5=3.0V $ and the total resistance is $ R=0.5+0.25+2.25=3.0\text{ }\Omega . $ Hence, the current in the circuit is $ I=\frac{E}{R}=\frac{3.0}{3.0}=1.0A $ Potential difference across the terminals of the first cell is $ {{V}_{1}}=E-I{{r}_{1}}=1.5-(1.0)\times (0.5)=1.0\,V $ Potential difference across the terminals of the second cell is $ {{V}_{2}}=E-I{{r}_{2}}=1.5-(1.0)\times (0.25)=1.25\,V $