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  4. Two cells are connected between points A and B as shown. Cell 1 has emf of 12 V and internal resistance of 3 Ω. Cell 2 has emf of 6 V and internal resistance of 6 Ω. An external resistor R of 4 Ω is connected across A and B. The current flowing through R will be A.

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Q. Two cells are connected between points $A$ and $B$ as shown. Cell 1 has emf of $12\, V$ and internal resistance of $3 \, \Omega$. Cell 2 has emf of $6 \, V$ and internal resistance of $6 \, \Omega$. An external resistor $R$ of $4\, \Omega$ is connected across $A$ and $B$. The current flowing through $R$ will be ___ $A$.Physics Question Image

JEE MainJEE Main 2023Current Electricity

Solution:

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$ E _{ eq }=\frac{\frac{12}{3}-\frac{6}{6}}{\frac{1}{3}+\frac{1}{6}} $
$ E _{ eq }=6 V$
$ r _{ eq }=2 \Omega $
$ R =4 \Omega$
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