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Q. Two cars moving in opposite directions approach each other with speed of $22\,ms^{- 1}$ and $16.5\,ms^{- 1}$ respectively. The driver of the first car blows a horn having a frequency $400\,Hz$ . The frequency heard by the driver of the second car is [velocity of sound $340\,ms^{- 1}$ ]:

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
As we know for given condition
$f_{\text{app}}=f_{0}\left(\frac{v + v_{\text{observer} }}{v - v_{\text{source} }}\right)=400\left(\frac{340 + 16 .5}{340 - 22}\right)$
$f_{\text{app} }=448\,Hz$