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Q. Two cars A and B are moving away from each other in opposite directions. Both the cars are moving with a speed of $20 \,ms^{-1}$ with respect to the ground. If an observer in car A detects a frequency $2000 \,Hz $ of the sound coming from car B, what is the natural frequency (in Hz) of the sound source in car B?
(speed of sound in air $=340\, ms^{-1})$

Waves

Solution:

$f ' =f \frac {v-v_{0}}{v+v_{s}}$
or $2000 = f \frac {340-20}{340+20}$
$\therefore f = 2250 \,Hz$