Question

Two cards are drawn one by one from a pack of cards. The probability of getting first card an ace and second a coloured one is (before drawing second card first card is not placed again in the pack):

• A. $ 4/13 $
• B. $ 1/26 $
• C. $ 5/52 $
• D. $ 5/221 $

Answer 1

Answer: (D)

Let $E_{1}=$ Event of getting an ace card
$\therefore P\left(E_{1}\right)=\frac{4}{52}$
And $E_{2}=$
Event of getting an coloured card
$P\left(E_{2}\right)=\frac{15}{51} $
$\therefore $ Required probability $=\frac{4}{52} \times \frac{15}{51}$
$=\frac{5}{221}$