Thank you for reporting, we will resolve it shortly
Q.
Two capillary tubes $P$ and $Q$ are dipped vertically in water. The height of water level in capillary tube $P$ is $\frac{2^{ rd }}{3}$ of the height in capillary
tube $Q$. The ratio of their diameter is
$r=\frac{2 T \cos \theta}{\rho g h}$
As we know $r \propto \frac{1}{h}$
$\frac{ r _{ P }}{ r _{ Q }}=\frac{ h _{ Q }}{ h _{ P }}=\frac{ h }{\frac{2}{3} h } $
$\Rightarrow \frac{ r _{ p }}{ r _{ Q }}=\frac{3}{2}$