1. Tardigrade
  2. Question
  3. Physics
  4. Two capacitors of capacitances C1 and C2 are connected across 200 V power supply. The potential drop across C1 is 120 V. A capacitor of capacitance 2 μ F is connected in parallel with C1 and the potential drop across C2 becomes 160 V. What are the values of C1 and C2 in μ F ?

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Q. Two capacitors of capacitances $C_1$ and $C_2$ are connected across $200 \,V$ power supply. The potential drop across $C_1$ is $120\, V. A$ capacitor of capacitance $2\,\mu F$ is connected in parallel with $C_1$ and the potential drop across $C_2$ becomes $160\, V$. What are the values of $C_1$ and $C_2$ in $\mu F$ ?

Electrostatic Potential and Capacitance

Solution:

Initially the charge is same on both capacitors.
Therefore, 120 $C_1$ = 80 $C_2$. Afterwards $(C_1+2)$ 40 = 160 $C_2$.
This gives $ C_1 = 0.4 \, \mu $F and $C_2 = 0.6\, \mu $F.