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  4. Two capacitors, each having capacitance 40 μ F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 μ F. The value of K will be :

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Q. Two capacitors, each having capacitance $40 \mu F$ are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant $K$ such that the equivalence capacitance of the system became $24 \mu F$. The value of $K$ will be :

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Solution:

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$ C _{ eq }=\frac{ C ( KC )}{ C + KC }=\frac{ KC }{ K +1} $
$ 24=\frac{ K 40}{ K +1} $
$ {[ K =1 \cdot 5]}$