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Q.
Two bulbs operating on standard voltage $ 110\,V $ have resistances in the ratio $ 9:16 $ . The ratio of brightness of light from them is
J & K CETJ & K CET 2014Current Electricity
Solution:
Power $=\frac{V^{2}}{R}$
As $V$ is same for both bulbs,
so, Power $\propto \frac{1}{R}$
so Intensity $\propto \frac{1}{R}$
$\Rightarrow $ So, $\frac{I_{1}}{I_{2}}=\frac{R_{2}}{R_{1}}$
$=\frac{16}{9}$