Question

Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is

• A. $\frac{2 \pi }{3}$
• B. $\pi $
• C. $\frac{\pi }{3}$
• D. None of these

Answer 1

Answer: (A)

Displacement from mean position
$=A-\left(\frac{2 - \sqrt{3}}{2}\right)A=\frac{\sqrt{3}}{2}A$ So phase of the particle which is going to
$\text{ wards }+x\text{ is }\phi_{1}=\frac{\pi }{3}$
$\text{ phase difference }=\frac{5 \pi }{3}-\frac{\pi }{3}$
$=\frac{4 \pi }{3}\text{ or }\left(2 \pi - \frac{4 \pi }{3}\right)$
$=\frac{4 \pi }{3}\text{ or }\frac{2 \pi }{3}$