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Q. Two bodies of masses $ m_{1} $ and $ m_{2} $ have equal momentum. Their kinetic energies $ E_{1} $ and $ E_{2} $ are in the ratio

Chhattisgarh PMTChhattisgarh PMT 2010

Solution:

Kinetic energy $E=\frac{P^{2}}{2 m}$
if bodies possess equal linear momenta,
then $E \propto \frac{1}{m}$
ie, $\frac{E_{1}}{E_{2}}=\frac{m_{2}}{m_{1}}$