Q. Two bodies having masses $ m_{1}=40\,g$ and $m_{2}=60\,g $ are attached to the ends of a string of negligible mass and suspended from massless pulley. The acceleration of the bodies is:
Delhi UMET/DPMTDelhi UMET/DPMT 2005Laws of Motion
Solution:
Let a be acceleration in the masses and $T$ be the tension in the string. The equations of motion are
$m_{2}=g-T=m_{2} a$ ... (i)
$T-m_{1} g=m_{1} a$ ... (ii)
From Eqs. (i) and (ii), we get
$a=\frac{m_{2}-m_{1}}{m_{1}+m_{2}} g$
Given, $m_{2}=60\, g,\, m_{1}=40\, g,\, g=10\, m / s ^{2}$
$\therefore a=\frac{60-40}{(60+40)} \times 10=2\, m / s ^{2}$
