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Q. Two blocks of masses $5\, kg$ and $2\, kg$ are connected by a spring of negilible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of $7\, m / s$ to the heavier block in the direction of the lighter block. The velocity of the centre of mass is

System of Particles and Rotational Motion

Solution:

$v_{cm} =\frac{m_{1} v_{1}+m_{2} v_{2}}{m_{1}+m_{2}}$
$=\frac{5(7)+2(0)}{7}=5\, m / s$