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  4. Two blocks of masses 10 kg and 20 kg are connected by a massless string and are placed on a smooth horizontal surface as shown in the figure. If a force F=600 N is applied to 10 kg block, if a force F is applied to 20 kg block, then the tension in the string is

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Q. Two blocks of masses $10\, kg$ and $20 \,kg$ are connected by a massless string and are placed on a smooth horizontal surface as shown in the figure. If a force $F=600$ $N$ is applied to $10\, kg$ block, if a force $F$ is applied to $20 \,kg$ block, then the tension in the string isPhysics Question Image

Laws of Motion

Solution:

Here, $m_(1)=10kg, m=20kg, F=600N$
Let T be tension of the string and a be common acceleration of the system.
$a=\frac{F}{m_1+m_2}=\frac{600N}{10kg+20kg}=\frac{600}{30}ms^{-2}=20ms^{-2}$
When force F is applied on $10kg$ block, then the tension in the string is $T_2=m_2a=(20kg)(20ms^{-2})=400N$
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