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  4. Two blocks are in contact on a frictionless table. One has mass m and other 2 m . A force F is applied on 2 m as shown in figure. Next the same force F is applied from the right on m . In the two cases respectively, the ratio of the force of contact between the two blocks will be <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-yfujpqlznzadwdgv.jpg />

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Q. Two blocks are in contact on a frictionless table. One has mass $m$ and other $2 \,m$ . A force $F$ is applied on $2 \,m$ as shown in figure. Next the same force $F$ is applied from the right on $m$ . In the two cases respectively, the ratio of the force of contact between the two blocks will be
Question

NTA AbhyasNTA Abhyas 2022Laws of Motion

Solution:

When force $F$ is applied on $2 \,m$ from left, contact force,
$F_1=\frac{m}{m+2 m} F=\frac{F}{3}$
When force $F$ is applied on $m$ from right, contact force
$F_2=\frac{2 m}{m+2 m} F=\frac{2 F}{3}$
$\therefore F_1: F_2=1: 2$