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Q. Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force F applied on the upper string produces an acceleration of $2 \,m/s^{2}$ in the upward direction in both the blocks. If $T$ and $T$ be the tensions in the two parts of the string, then
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Laws of Motion

Solution:

FBD of mass 2 kg FBD of mass 4 kg
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$T-T'-20=4 \ldots$(i)
$T'-40=8 \ldots $ (ii)
By solving (i) and (ii) $T'=47.23\,N$ and
$T=70.8\,N$