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Q. Two black bodies A and B have equal surface areas and are maintained at temperatures 27°C and 177°C respectively. What will be the ratio of the thermal energy radiated per second by A to that by B?

WBJEEWBJEE 2019Thermal Properties of Matter

Solution:

$Q=\sigma AT^{4}, \frac{Q_{1}}{Q_{2}} =\left(\frac{T_{1}}{T_{2}}\right)^{4} =\left(\frac{273+27}{273+177}\right)^{4} =\left(\frac{300}{450}\right)^{4} =\left(\frac{2}{3}\right)^{4} =\frac{16}{81}$