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  4. Two billiard balls of mass 0.05 kg each moving in opposite directions with 10 ms -1 collide and rebound with the same speed. If the time duration of contact is t =0.005 s, then what is the force exerted on the ball due to each other?

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Q. Two billiard balls of mass $0.05\, kg$ each moving in opposite directions with $10 \, ms ^{-1}$ collide and rebound with the same speed. If the time duration of contact is $t =0.005 \, s$, then what is the force exerted on the ball due to each other?

JEE MainJEE Main 2022Electrostatic Potential and Capacitance

Solution:

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Change in momentum of any one ball
$ |\Delta \overrightarrow{ P }|=2 \times 0.05 \times 10 $
$ |\Delta \overrightarrow{ P }|=1$
$ \left|\overrightarrow{ F }_{ av }\right|=\frac{|\Delta \overrightarrow{ P }|}{\Delta t } $
$ F _{ av }=200 \,N$