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  4. Two batteries of emf 4 V and 8 V with internal resistances 1 Ω and 2 Ω are connected in a circuit with a resistance of 9 Ω as shown in figure. The current and potential difference between the points P and Q are

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Q. Two batteries of emf $4 V$ and $8 V$ with internal resistances $1 \Omega$ and $2 \Omega$ are connected in a circuit with a resistance of $9 \Omega$ as shown in figure. The current and potential difference between the points $P$ and $Q$ arePhysics Question Image

AMUAMU 2002

Solution:

Applying Kirchhoffs law in the given loop
image
$-2 I+8-4-1 \times I-9 I=0$
$\Rightarrow I=\frac{1}{3} A$
Potential difference across $PQ$
$=\frac{1}{3} \times 9=3 V$