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  4. Two batteries of emf 4 V and 8 V with internal resistance 1 Ω and 2 Ω are connected in a circuit with resistance of 9 Ω as shown in figure. The current and potential difference between the points P and Q are

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Q. Two batteries of emf $4\, V$ and $8 \,V$ with internal resistance $1\, \Omega$ and $2\, \Omega$ are connected in a circuit with resistance of $9\, \Omega$ as shown in figure. The current and potential difference between the points $P$ and $Q$ arePhysics Question Image

AIPMTAIPMT 1988Current Electricity

Solution:

$I=\frac{8-4}{1+2+9}=\frac{4}{12}=\frac{1}{3} A$
$V_{P}-V_{Q}=4-\frac{1}{3} \times 3=3 $ Volt