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  4. Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2, respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is

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Q. Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2, respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is

Probability - Part 2

Solution:

Given : Probability of aeroplane I, scoring a target correctly i.e., P(I) = 0.3 probability of scoring a target
correctly by aeroplane II, i.e. P(II) = 0.2
$\therefore \, P( \bar{I} ) = 1 - 0.3 = 0.7$
$\therefore $ The required probability
$= P( \bar{I} \cap II ) = P( \bar{I} ).P(II) = 0.7 \times 0.2$
= 0.14