Question

Two adjacent plant cells are depicted below. A few statements regarding them are made. Mark the correct statement

cell A	cell B
$\psi$ = $1200\,kpa$	$\psi$ =$-800\,kpa$
$\psi_{P}=800\,kpa$	$\psi_{P}=600\,kpa$
$\psi_{S}=-2000\,kpa$	$\psi_{S}=-1400\,kpa$

• A. The Cell A has a higher water potential than B
• B. The direction of movement of water by osmosis will be from Cell A to Cell B
• C. At equilibrium, the two cells will have a potential value of -1700 KPa
• D. Assuming that the solute potentials of the two cells do not change at equilibrium, the pressure potential of Cell B will be 400 KPa.

Answer 1

Answer: (D)

Correct answer is (d) Assuming that the solute potentials of the two cells do not change at equilibrium, the pressure potential of Cell B will be 400 KPa.