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  4. Twelve one-rupee coins are put on top of each other on a table, where mass of each coin is 20 g. The reaction of the 7 th coin (counted from bottom) on the 8 th coin is [take, g=10 m / s 2 ]

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Q. Twelve one-rupee coins are put on top of each other on a table, where mass of each coin is $20\, g$. The reaction of the $7 th$ coin (counted from bottom) on the $8 th$ coin is [take, $g=10\, m / s ^{2}$ ]

Laws of Motion

Solution:

According to question, $7th$ coin is under the weight of $5$ coins above it.
Hence, reaction of the $7th$ coin on the $8th$ coin
$=$ force on the $7th$ coin due to 8th coin
$=$ weight of $5$ coins
$=5\, m g=5 \times 20 \times 10^{-3} \times 10= 1\, N$
$\left[\because m=20\, g =20 \times 10^{-3} kg \right]$