Q.
Truth table for the given circuit in figure is:
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
A
B
$C = A . B$
$D = \bar{A}B$
$E = C +D$
0
0
0
0
0
0
1
0
1
1
1
0
0
0
0
1
1
1
1
1
| A | B | $C = A . B$ | $D = \bar{A}B$ | $E = C +D$ |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 1 | 1 |