Q.
Truth table for the given circuit in figure is
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
Truth table for the given circuit is
A
B
$C = A\cdot B$
$D = \bar{A} \cdot B$
E = C+D
0
0
0
0
0
0
1
0
1
1
1
0
0
0
0
1
1
1
0
1
Hence, option (c) is correct.
| A | B | $C = A\cdot B$ | $D = \bar{A} \cdot B$ | E = C+D |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 0 | 1 |