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Q. Total vapor pressure of mixture of $1 \,mol A\left(p_{A}^{\circ}=150\right.$ torr $)$ and $2\, mol B\left(p_{B}^{\circ}=240\right.$ torr $)$ is $200$ torr. In this case,

Solutions

Solution:

$p_{s}=p_{A}^{\circ} x_{A}+p_{B}^{\circ} x_{B}$

$=\left(150 \times \frac{1}{3}\right)+\left(240 \times \frac{2}{3}\right)=210$

$\Delta p_{\text{mix}}=p_{\exp }-p_{\text {theo }}=- ve$