Thank you for reporting, we will resolve it shortly
Q.
Total number of ways in which five $'+'$ and three $'-'$ signs can be arranged in a line such that no two $'-'$ sign occur together is
AMUAMU 2013Permutations and Combinations
Solution:
$+ \,\, + \,\, +\,\, +\,\,+$
On fixing five positive signs, there are $6$ places for negative signs.
$\therefore$ Required number of ways $={ }^{6} C_{3}=20$