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Chemistry
Total charge required for the oxidation of two moles Mn 3 O 4 into MnO 42 in presence of alkaline medium is-
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Q. Total charge required for the oxidation of two moles $Mn _{3} O _{4}$ into $MnO _{4}^{2}$ in presence of alkaline medium is-
Electrochemistry
A
5 F
22%
B
10 F
31%
C
20 F
27%
D
None of these
21%
Solution:
$16 OH ^{-}+ Mn _{3} O _{4} \rightarrow 3 MnO _{4}^{2-}+8 H _{2} O +10 e ^{-}$
1 mol electron required is 10
$2 mol =2 \times 10=20$
Charge required
$=20 \times F =20 F$