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  4. Total charge required for the oxidation of two moles Mn3O4 into MnO42 - in presence of alkaline medium is

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Q. Total charge required for the oxidation of two moles $Mn_{3}O_{4}$ into $MnO_{4}^{2 -}$ in presence of alkaline medium is

NTA AbhyasNTA Abhyas 2022

Solution:

1 mole $Mn_{3}O_{4}lose\left(6 - \frac{8}{3}\right)\times 3=10$ mole $e^{-}$ ,
so total charge required $=2\times 10=20F$