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Q. Torque of equal magnitude is applied to a solid cylinder and a solid sphere, both having the same mass and radius. Both of them are free to rotate about their axis of symmetry. If $\alpha _{1}$ and $\alpha _{2}$ are the angular accelerations of the cylinder and the sphere respectively, then the ratio $\frac{\alpha _{1}}{\alpha _{2}}$ will be

NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion

Solution:

$\alpha _{1}=\frac{M R^{2}}{2}$ and $\alpha _{2}=\frac{2}{5}MR^{2}$
$\therefore \frac{\alpha _{1}}{\alpha _{2}}=\frac{4}{5} \, $