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Q. Torque of equal magnitude is applied to a solid cylinder and a solid sphere, both having the same mass and radius. Both of them are free to rotate about their axis of symmetry. If $\alpha_{1}$ and $\alpha_{2}$ are the angular accelerations of the cylinder and the sphere respectively, then the ratio $\frac{\alpha_{2}}{\alpha_{1}}$ will be _______.

System of Particles and Rotational Motion

Solution:

$I _{2} \alpha_{2}= I _{1} \alpha_{1}$
$ \frac{2}{5} MR ^{2} \alpha_{2}=\frac{ MR ^{2}}{2} \alpha_{1} $
$\therefore \frac{\alpha_{2}}{\alpha_{1}}=\frac{5}{4}=1.25$