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Q. To increase the frequency from $100\, Hz$ to $400\, Hz$, the tension of string will be

Rajasthan PETRajasthan PET 2001

Solution:

$ n\propto \sqrt{T} $
$ \therefore $ $ \frac{{{T}_{1}}}{{{T}_{2}}}=\frac{n_{1}^{2}}{n_{2}^{2}}={{\left( \frac{100}{400} \right)}^{2}}=\frac{1}{16} $
$ \Rightarrow $ $ {{T}_{2}}=16{{T}_{1}} $