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Q. To get maximum current through a resistance of $2.5 \, \Omega$ , one can use $m \, $ rows of cells, each row having $n \, $ cells. The internal resistance of each cell is $0.5 \, \Omega$ . The values of $n$ and $m$ , if the total number of cells is $45$ , are

NTA AbhyasNTA Abhyas 2022

Solution:

$R=2.5\Omega \, , \, r=0.5\Omega$
no of rows $=m, \, $ no of columns in each row $=n$
$i=\frac{n E}{R + n r / m}$ total cells $\Rightarrow mn=45$
for max. current; $R=nr/m, \, mR=nr$
$m=3, \, n=15$