Q.
To get an output $Y = 1$ in given circuit which of the following input will be correct?
A
B
C
(a)
1
0
0
(b)
1
0
1
(c)
1
1
0
(d)
0
1
0
| A | B | C | |
|---|---|---|---|
| (a) | 1 | 0 | 0 |
| (b) | 1 | 0 | 1 |
| (c) | 1 | 1 | 0 |
| (d) | 0 | 1 | 0 |
AIPMTAIPMT 2012Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
The Boolean expression of the given circuit is
$Y =( A + B)C$
The table truth of the given inputs is as shown in the table.
Inputs
output
A
B
C
$Y=\left(A+B\right)\cdot C$
1
0
0
0
1
0
1
1
1
1
0
0
0
1
0
0
From the above truth table it is clear that $Y = 1$, when $A = 1, B = 0$ and $C = 1$
| Inputs | output | ||
|---|---|---|---|
| A | B | C | $Y=\left(A+B\right)\cdot C$ |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 |
| 0 | 1 | 0 | 0 |