Question

To get an output $1$ from the circuit shown in the figure, the input must be

• A. $A=0, \, B=1, \, C=0$
• B. $A=1, \, B=0, \, C=0$
• C. $A=1, \, B=0, \, C=1$
• D. $A=1, \, B=1, \, C=0$

Answer 1

Answer: (C)

The Boolean expression for the given combination is output $Y=\left(A + B\right).C$
Hence, $A=1,B=0, \, C=1$
or other combination can be $A = 1 , B = 1 , C = 1$