1. Tardigrade
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  3. Chemistry
  4. To a clear solution of compound (X), a solution of BaCl2 is added and a heavy white precipitate is formed which does not dissolve in dil. HCl. The compound (X) is

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Q. To a clear solution of compound $ (X),$ a solution of $ BaCl_2$ is added and a heavy white precipitate is formed which does not dissolve in dil. $ HCl. $ The compound $ (X)$ is

The s-Block Elements

Solution:

$ SO^{2-}_4 + BaCl \to \underset{\text {Insoluble in dil. HCl}}{BaSO_4↓} + 2Cl^- $