Thank you for reporting, we will resolve it shortly
Q.
Titanium shows magnetic moment of 1.73 B.M.in its compound. What is the oxidation numberof Ti in the compound ?
The d-and f-Block Elements
Solution:
Magnetic moment = $\sqrt{n(n + 2)}$ B.M.
Magnetic moment of Ti ion = 1.73 BM
$\sqrt{n(n + 2)}$ . = 1.73
$ n(n + 2)$ = 3
$n$ = 1
$\therefore $ Ti ion has 1 unpaired electron i.e., $3d^1$ con- figuration.
$\therefore $ Complete configuration of $Ti^{3+}$ ion is ; $Ti^{3+}$ (Z = 22) : $[Ar]^{18} \, 3d^1$