Question

Time period of revolution of an electron in $n^{\text {th }}$ orbit in a hydrogen like atom is given by $T=\frac{T_{0} n^{a}}{Z^{b}} \cdot Z=$ atomic number

• A. $T_{0}=1.5 \times 10^{-16} s , a =3$
• B. $T_{0}=6.6 \times 10^{15} s , a =3$
• C. $T_{0}=1.51 \times 10^{-16} s , b=3$
• D. $T_{0}=6.6 \times 10^{15} s , b=3$

Answer 1

Answer: (A)

$T=\frac{T_{0} n^{a}}{Z^{b}} $
$T_{n}=\frac{T_{0} n^{3}}{Z} $
$T_{0}=1.51 \times 10^{-16} \,s $
$ a=3$