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Mathematics
Time period T of a simple pendulum of length l is given by T=2π√(l/g). If the length is increased by 2 %, then an approximate change in the time period is
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Q. Time period $T$ of a simple pendulum of length $l$ is given by $T=2\pi\sqrt{\frac{l}{g}}.$ If the length is increased by $2\%$, then an approximate change in the time period is
WBJEE
WBJEE 2016
Application of Derivatives
A
$2\%$
B
$1\%$
C
$\frac{1}{2}\%$
D
None of these
Solution:
$\frac{dT}{d\ell}=\frac{2\pi}{\sqrt{g}}. \frac{1}{2\sqrt{\ell}}$
$\therefore \Delta T=\frac{dT}{d\ell}. \Delta\ell=\frac{\pi}{\sqrt{g\ell}}.\left(\frac{2\ell}{100}\right)$
$=2\pi\sqrt{\frac{\ell}{g}}. \frac{1}{100}=\frac{T}{100}$
$\therefore \frac{\Delta T}{T}=\frac{1}{100}$
$\therefore 1\%$