Question

$[Ti(H_2O)_6]^{2+}$ is a $3d^2$ system, the value of crystal field stabilization energy decreases by

• A. $4 \times 10^{-1} \, \Delta_o$
• B. $4.0 \, \Delta_o$
• C. $8.0\, \Delta_o$
• D. $8 \times 10^{-1} \, \Delta_o$

Answer 1

Answer: (D)

For a $3d^2$ system, electrons will go into more stable $t_{2g}$ orbitals and each electron going into a $t_{2g}$ orbital is stabilized by $0.4 \Delta_o$ i.e., 2 electrons will be stabilized by $0.8 \Delta_o$ or $8 \times 10^{-1} \Delta_o$'