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Q. Three point masses, each of mass $m$ are placed at the corners of an equilateral triangle of side The moment of inertia of this system about, an axis along one side of the triangle is

Bihar CECEBihar CECE 2010System of Particles and Rotational Motion

Solution:

Moment of inertia of system about side $A B$ is
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$I=m(0)^{2}+m(0)^{2}+m\left(\frac{\sqrt{3}}{2} a\right)^{2}$
$=\frac{3}{4} m a^{2}$