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Q. Three point masses $1.0kg$ , $1.5kg$ and $2.5kg$ are placed at the vertices of a right-angle triangle of sides $4.0cm$ , $3.0cm$ and $5.0cm$ , as shown in the figure. The centre of mass of the system is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Let us assume that the origin of the coordinate system is at the location of $1kg$ mass, then
Solution
$x_{cm}=\frac{1 \times 0 + 1 . 5 \times 3 + 2 . 5 \times 0}{5}=0.9cm$
$y_{cm}=\frac{1 \times 0 + 1 . 5 \times 0 + 2 . 5 \times 4}{5}=2cm$