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  4. Three phtodiodes D 1, D 2 and D 3 are made of semiconductors having band gaps of 2.5 eV, 2 eV and 3 eV respectively. Which one will be able to detect light of wavelength 600 nm?

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Q. Three phtodiodes $D _{1}, D _{2}$ and $D _{3}$ are made of semiconductors having band gaps of $2.5 \,eV$, $2\, eV$ and $3\, eV$ respectively. Which one will be able to detect light of wavelength $600 \,nm?$

KCETKCET 2021Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$ E _{1}=2.5\, eV$
$ E _{2}=2 \,eV $
$ E _{3}=3\, eV$
$\lambda=600\, nm $
$ \therefore E =\frac{1242}{\lambda_{ nm }}=\frac{1242}{600} eV $
$=2.07\, eV $
$( E _{1} $ and $E _{3}$ is $ > E $
Only $D _{2}$ will detect