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Q. Three particles start from origin at the same time with a velocity $2\, ms^{-1}$ along positive $x$-axis, the second with a velocity $6\, ms^{-1}$ along negative $y$-axis. Find the velocity of the third particle along $x = y$ line so that the three particles may always lie in a straight line.

Motion in a Straight Line

Solution:

Slope $AB =$ slope $AC$
image
$\frac{2t - 0}{0 + 6t} = \frac{2t - \frac{vt}{\sqrt{2}}}{0 - \frac{vt}{\sqrt{2}}}$
Solve to get $v = 3\sqrt{2}\, m/s$