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Q. Three identical spherical shells, each of mass $m$ and radius $r$ are placed as shown in the figure. Consider an axis $XX^{′}$ which is touching the two shells and passing through the diameter of the third shell. The moment of inertia of the system consisting of these three spherical shells about $XX^{′}$ axis is:
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Total moment of inertia of the system,
$I=I_{1}+I_{2}+I_{3}$
$I_{2}=I_{3}=\frac{2}{3}mr^{2}+mr^{2}=\frac{5 m r^{2}}{3}$
$I_{1}=\frac{2}{3}mr^{2}$
$\therefore I=2\times 5\frac{m r^{2}}{3}+\frac{2}{3}mr^{2}$
$=\frac{12 m r^{2}}{3}=4mr^{2}$