Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Three identical blocks each of mass $M$ are along a frictionless table and a force $F$ is acting as shown. Which of the following statement is false?

Question

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

The acceleration of the system in rightward direction is
$a=\frac{F}{m_{A} + m_{B} + m_{C}}=\frac{F}{3 M}$
For A
From force diagram of A, the Net force on A $=F-F_{1}$
$=m_{1}a=\frac{M F}{3 M}=\frac{F}{3}$

Solution
The force interaction between A and B is $F_{1}=F-\frac{F}{3}=\frac{2 F}{3}$