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  4. Three distinct vertices are randomly chosen among the vertices of cube then, the probability that thy are vertices of an equilateral triangle is (1/β) then β is

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Q. Three distinct vertices are randomly chosen among the vertices of cube then, the probability that thy are vertices of an equilateral triangle is $\frac{1}{\beta}$ then $\beta$ is

Probability

Solution:

Correct answer is '7'