Question

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides.

• A. $60^{\circ}$, equilateral triangle
• B. $120^{\circ}$, equilateral triangle
• C. $30^{\circ}$, an isosceles triangle
• D. $120^{\circ}$, an obtuse angled triangle

Answer 1

Answer: (B)

In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given

$\theta=\frac{360}{N}=\frac{360}{3}=120^{\circ}$