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Q. Three closed vessels $A, B$ and $C$ are at the same temperature $T$ and contain gases which obey the Maxwellian distribution of velocities. Vessel $A$ contains only $O _{2}, B$ only $N _{2}$ and $C$ a mixture of equal quantities of $O _{2}$ and $N _{2}$. If the average speed of the $O _{2}$ molecules in vessel $A$ is $V_{1}$, that of the $N _{2}$ molecules in vessel $B$ is $V_{2}$, the average speed of the $O _{2}$ molecules in vessel $C$ is (where $M$ is the mass of an oxygen molecule)

Kinetic Theory

Solution:

Average speed of gas molecule $v_{ av }=\sqrt{\frac{8 k T}{\pi m}} .$
It depends on temperature and molecular mass.
So the average speed of oxygen will be same in vessel $A$ and vessel $C$ and that is equal to $V_{1}$.